A man of weight 80 kg is standing in an elevator which is moving with an acceleration of `6m//s^(2)` in upward direction. The apparent weight of the man will be `(g=10m//s^(2))`

Explanation

To find the apparent weight of a man standing in an elevator that is accelerating upwards, we can follow these steps:

### Step-by-Step Solution

1. **Identify the Given Values:**
- Weight of the man (mass, \( m \)) = 80 kg
- Acceleration of the elevator (\( a \)) = 6 m/s² (upward)
- Acceleration due to gravity (\( g \)) = 10 m/s²

2. **Calculate the Gravitational Force:**
The gravitational force acting on the man (weight) can be calculated using the formula:
\[ F_g = m \cdot g \]
Substituting the values:
\[ F_g = 80 \, \text{kg} \times 10 \, \text{m/s}^2 = 800 \, \text{N} \]

3. **Calculate the Apparent Weight:**
When the elevator accelerates upwards, the apparent weight (normal force, \( N \)) can be calculated using the formula:
\[ N = m \cdot (g + a) \]
Substituting the values:
\[ N = 80 \, \text{kg} \times (10 \, \text{m/s}^2 + 6 \, \text{m/s}^2) = 80 \, \text{kg} \times 16 \, \text{m/s}^2 \]
\[ N = 1280 \, \text{N} \]

4. **Conclusion:**
The apparent weight of the man while the elevator is accelerating upwards is \( 1280 \, \text{N} \).

### Final Answer:
The apparent weight of the man is \( 1280 \, \text{N} \).

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