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Consider a hypothetical gas with molecul...

Consider a hypothetical gas with molecules that can move along only a single axis. The following table gives four situations. The velocities in meter per second of such a gas having four molecules are given below. The plus and minus sign refer to the direction of the velocity along the axis.
`{:(ul("Situation Velocities"),,,,),("a -2 +3 -4 +5",,,,),(-------------,,,,),("b +1 -3 +4 -6",,,,),(-------------,,,,),("c +2 +3 +4 +5",,,,),(-------------,,,,),("d +3 +3 -4 -5",,,,),(-------------,,,,):}`
In which situation root-mean-square speed of the molecules is greatest

A

`A`

B

`B`

C

`C`

D

`D`

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The correct Answer is:
To find the situation with the greatest root-mean-square (RMS) speed of the molecules in the hypothetical gas, we will calculate the RMS speed for each situation using the formula: \[ V_{RMS} = \sqrt{\frac{V_1^2 + V_2^2 + V_3^2 + V_4^2}{4}} \] Since the denominator (4) is constant for all situations, we can focus on maximizing the numerator \(V_1^2 + V_2^2 + V_3^2 + V_4^2\). ### Step-by-step calculation: **Situation A:** - Velocities: \(-2, +3, -4, +5\) - Calculate squares: \[ V_1^2 = (-2)^2 = 4 \] \[ V_2^2 = (+3)^2 = 9 \] \[ V_3^2 = (-4)^2 = 16 \] \[ V_4^2 = (+5)^2 = 25 \] - Sum of squares: \[ V_1^2 + V_2^2 + V_3^2 + V_4^2 = 4 + 9 + 16 + 25 = 54 \] **Situation B:** - Velocities: \(+1, -3, +4, -6\) - Calculate squares: \[ V_1^2 = (+1)^2 = 1 \] \[ V_2^2 = (-3)^2 = 9 \] \[ V_3^2 = (+4)^2 = 16 \] \[ V_4^2 = (-6)^2 = 36 \] - Sum of squares: \[ V_1^2 + V_2^2 + V_3^2 + V_4^2 = 1 + 9 + 16 + 36 = 62 \] **Situation C:** - Velocities: \(+2, +3, +4, +5\) - Calculate squares: \[ V_1^2 = (+2)^2 = 4 \] \[ V_2^2 = (+3)^2 = 9 \] \[ V_3^2 = (+4)^2 = 16 \] \[ V_4^2 = (+5)^2 = 25 \] - Sum of squares: \[ V_1^2 + V_2^2 + V_3^2 + V_4^2 = 4 + 9 + 16 + 25 = 54 \] **Situation D:** - Velocities: \(+3, +3, -4, -5\) - Calculate squares: \[ V_1^2 = (+3)^2 = 9 \] \[ V_2^2 = (+3)^2 = 9 \] \[ V_3^2 = (-4)^2 = 16 \] \[ V_4^2 = (-5)^2 = 25 \] - Sum of squares: \[ V_1^2 + V_2^2 + V_3^2 + V_4^2 = 9 + 9 + 16 + 25 = 59 \] ### Summary of Results: - Situation A: \(54\) - Situation B: \(62\) - Situation C: \(54\) - Situation D: \(59\) ### Conclusion: The situation with the greatest root-mean-square speed is **Situation B** with a sum of squares equal to \(62\).

To find the situation with the greatest root-mean-square (RMS) speed of the molecules in the hypothetical gas, we will calculate the RMS speed for each situation using the formula: \[ V_{RMS} = \sqrt{\frac{V_1^2 + V_2^2 + V_3^2 + V_4^2}{4}} \] Since the denominator (4) is constant for all situations, we can focus on maximizing the numerator \(V_1^2 + V_2^2 + V_3^2 + V_4^2\). ...
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