Container A holds an ideal gas at a pressure `1 xx10^5` Pa and at 300 K. Container B whose volume is 4 times the volume of A has the same ideal gas at 400 K and at a pressure of `5xx10^5`

The valve V is adjusted to allow the pressure to equalize, but the temperature of each container is kept constant at the initial value, then the pressure in the two containers is :

Options

A. `4 xx 10^5` Pa
B. `3 xx 10^5` Pa
C. `2 xx10^5` Pa
D. `1 xx 10^5` Pa

Answer

A

Explanation

`rArr" "(10^2V)/(R(300))+(5xx10^5(4V))/(R(400)) =P/R (V/300+(4V)/(400))" "rArr" "10^5 (400 + 6000)=P (400 + 1200)`
`rArr" "P = (64 00)/(1600) xx 10^5 rArr P = 4 xx10^5 Ps`