1 mole of a gas with `lamda=7/5` is mixed with 1 mole of gas with `lamda=(5)/(3),` the value of `lamda` of the resulting mixture of

Options

A. `7/5`
B. `2/5`
C. `24/16`
D. `12/7`

Answer

C

Explanation

Using the relation, `(n_1+n_2)/(gamma-1)=(n_1)/(gamma-1)+(n_2)/(gamma-1)`
`(1+1)/(gamma-1)=(1)/((5"/"3-1))+(1)/((1)/((7"/"5-1))` or `(2)/(gamma-1)=(3)/(2)+(5)/(2)=4 implies gamma=((3)/(2))=(24)/(26)`.