Consider an ideal gas confined in an isolated closed chamber. As the gas undergoes an adiabatic expansion the average time of collision between molecules increases as `V^(q)`, where V is the volume of the gas. The value of q is :
`(gamma = C_(p)/C_(v))`

Options

A. `(3 gamma + 5)/6`
B. `(3 gamma - 5)/6`
C. `(gamma + 1)/2`
D. `(gamma - 1)/2`

Answer

C

Explanation

`tau=(lambda)/(V_(ms))=(1)/(sqrt(2)pid^2(N/V)sqrt((3RT)/(M)))" ""…………….."(i)`
`tau propto (V)/(sqrt(T))" ""……………."(ii)`
`TV^(gamma-1)=k" ""…………."(iii) implies tau propto V^((gamma+1)/(2))`.