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The temperature of an open room of volum...

The temperature of an open room of volume `30 m^(3)` increases from `17^(@)C to 27^(@)C` due to sunshine. The atmospheric pressure in the room remains `1 xx 10^(5) Pa`. If `n_(i) and n_(f)` are the number of molecules in the room before and after heating then `n_(f) - n_(i)` will be

A

`1. 38 xx10^(23)`

B

`2.5 xx10^(25)`

C

`-2.5 xx10^(25)`

D

`-1.61 xx10^(23)`

Text Solution

Verified by Experts

The correct Answer is:
C

From `pv=nRT-(N)/(N_(A))RT`
We have, `n_f-n_i=(pVN_A)/(RT_f)-(pVN_A)/(RT_i) implies n_f-n_i=(10^5xx 30)/(8.2)xx 6.02xx10^(23)*((1)/(300)-(1)/(290))`
`= -2.5xx10^(25)" ":. Trianglen= -2.5xx10^(25)`.
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