Two kg of a monoatomic gas is at a pressure of `4 xx 10^(4) N//m^(2)`. The density of the gas is `8 kg//m^(3)`. What is the order of energy of the gas due to its thermal motion ?

Options

A. `10^5 J`
B. `10^4 J`
C. `10^2 J`
D. `10^6 J`

Answer

B

Explanation

`U=(f)/(2)nRT= (f)/(2)PV=(f)/(2)xx Pxx (" mass ")/(" density ") implies U= (3)/(2)xx4 xx10^(4)xx(2)/(8)J= 1.5 xx 10^(4)J`.