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An ideal gas is enclosed in a cylinder a...

An ideal gas is enclosed in a cylinder at pressure of 2atm and temperature, 300K. The mean time between two successive collisions is `6xx10^(-8)` s. If the pressure is doubled and temperature is increased to 500K, the mean time between two successive collisions will be close to:

A

`4 xx10^(-8)s`

B

`3xx10^(-6)J`

C

`3 xx10^3 J`

D

`9 xx10^6 J`

Text Solution

Verified by Experts

The correct Answer is:
A
Time between successive collison =`t propto (sqrt(T))/(P)`
So, `6xx10^(-8)propto (sqrt(300))/(2)" and "t_2 propto (sqrt(500))/(4)`
Solving, `t=sqrt(15)xx 10^(-8) approx 4xx 10^(-8)` sec.
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