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Figure shows two processes a and b for a...

Figure shows two processes a and b for a given sample of a gas. If `DeltaQ_1`, `DeltaQ_2` are the amounts of heat absorbed by the system in the two cases and `DeltaU_1`, `DeltaU_2` are changes in internal energies respectively, then

A

`Delta Q_A gt Delta Q_B, Delta U_A=Delta U_B`

B

`Delta Q_A lt Delta Q_B, Delta Q_A ltDeltaU_B`

C

`Delta Q_A Delta Q_B, Delta U_A = Delta U_B`

D

`Delta Q_A gt Delta Q_B, Delta U_A gtDelta U_B`

Text Solution

Verified by Experts

The correct Answer is:
A
Area under curve process 'A' on P-V diagram is more. Hence
`W_(A) gt W_(B) :. Triangle Q_(A) gt triangleQ_(B) " & "triangleU_(A) = triangleU_(B)`.
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