The efficiency of a heat engine is `1//6`Its efficiency double when the temperature of sink decrease by `62^(@)C` its efficiency doubles.Then,What is the temperature of source?

Options

A. `99^@ C, 37^@ C`
B. `37^@ C, 99^@ C`
C. `62^@C, 124^@C`
D. `124^@ C, 62^@ C`

Answer

B

Explanation

`(1)/(6)=1-(T_2)/(T_1) implies (T_2)/(T_1)=(5)/(6)" ""…………"(A)`
`(1)/(3)=1-((T_2-62))/(T_1) implies ((T_2-62)/(T_1))= (2)/(3)" ""……………."(B)`
From (A) and (B)
`(1)/(6)= (62)/(T_1) implies T_1=372K" or "99^(@)C" "T_2= (5)/(6)xx372= 5xx62= 310K " or "37^(@)C`.