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A bat emits ultrasonic sound of frequency 100 kHz in air. If this sound meets a water surface, the wavelengths of the reflected and transmitted sound are (Speed of sound in air = 340 m `s^(-1)` and in water = 1500 m `s^(-1)` )

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After meeting the water surface, a portion of the wave is reflected back in air which then travels with speed of 340 m/s, and another portion of wave is transmitted in water which then travels with speed of 1486 m/s. Also, when sound travels from one medium to another, its frequency remains unchanged.
Wavelength in air `lamda_(a)=("speed of sound in air")/("Frequency of sound")`
`=(340m//s)/(100kHz)=3.4xx10^(-3)m`
Wavelength in water `lamda_(W)=("speed of sound in water")/("Frequency of sound")`
`=(1486m//s)/(100kHz)=1.49xx10^(-2)m`
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