The transverse displacement of a string (clamped at its two ends ) is given by
`y(x,t)=0.06sin((2pi)/(3))xcos(120pit)`
wherer x ,y are in m and t ini s. The length of the string is 1.5m and its mass is `3xx10^(-2)` kg. Answer the following: (i) Does the function represent a travelling or a stationary wave ?
(ii) Interpret the wave as a superimposition of two waves travelling in opposite directions. What are the wavelength, frequency and speed of propagation of each wave ?
(iii) Determing the tension in the string.

Explanation

To solve the problem step by step, we will address each part of the question systematically.

### Given:
The transverse displacement of a string is given by:
\[ y(x,t) = 0.06 \sin\left(\frac{2\pi}{3} x\right) \cos(120\pi t) \]
- Length of the string, \( L = 1.5 \, \text{m} \)
- Mass of the string, \( m = 3 \times 10^{-2} \, \text{kg} \)

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