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A string of mass 0.2 kg/m and length l= ...

A string of mass 0.2 kg/m and length l= 0.6 m is fixed at both ends and stretched such that it has a tension of 80 N. the string vibrates in 3 segments with maximum amplitude of 0.5 cm. the maximum transverse velocity amplitude is

A

1.57 m/s

B

6.28 m/s

C

3.14 m/s

D

9.42 m/s

Text Solution

Verified by Experts

The correct Answer is:
A
`l=(3lamda)/(2),v=sqrt((T)/(mu)),f=(v)/(lamda),v_(max)=(A_(max))omega=A_(max)(2pisqrt(T//mu))/((2l//3))=(0.5xx2pisqrt(80//0.2))/((2xx(0.6)/(3)))=1.57m//s`
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