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For a certain organ pipe three successiv...

For a certain organ pipe three successive resonance frequencies are observed at 425Hz, 595 Hz and 765Hz respectively. If the speed of sound air is 340m/s, then the length of the pipe is

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The correct Answer is:
1
Since frequencies are in odd number ratio, the pipe has to be a closed pipe
Ratio of three frequencies`=425:595:765`
`=5:7:9`
So fundamental frequency`=v=(425)/(5)=85Hz`
For fundamental frequency, `l=(v)/(4v)=(340)/(4xx85)=1m`
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