The tension in a string, obeying Hooke's law, is `x`. The speed of sound in the stretched string is `v`. If the tension in the string is increased to `1.5x`, the speed of sound will be

Options

A. 1.22v
B. 0.61v
C. 1.50v
D. 0.75v

Answer

A

Explanation

According to Hooke's law,`F_g propx["Restoring force "F_g," tension of spring"]`
Velocity of sound string
`v=sqrt((T)/(m))`
When m is the mass per unit length `therefore v/(v')=sqrt((T)/(T'))=implies v'=vsqrt((T')/(T))=vsqrt((1.5x)/(x))=1.22 v`