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A 20 cm long string, having a mass of 1....

A `20 cm` long string, having a mass of `1.0 g`, is fixed at both the ends. The tension in the string is `0.5 N`. The string is set into vibrations using an external vibrator of frequency `100 Hz` Find the separation (in cm) between the successive nodes on the string.
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The correct Answer is:
5
`v=sqrt((T)/(mu))=10 m//s , lambda=v/f=10/100=10 cm`
Distance between the successive nodes `=lambda//2=5cm`
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