Home
Class 12
PHYSICS
Average velocity of a particle moving in...

Average velocity of a particle moving in a straight line, with constant acceleration a and initial velocity `u` in first `t` seconds is.

A

` u+ (1)/(2) at `

B

` u+ at`

C

` (u+ at)/(2) `

D

` (u)/(2) `

Text Solution

AI Generated Solution

The correct Answer is:
To find the average velocity of a particle moving in a straight line with constant acceleration, we can follow these steps: ### Step 1: Understand the parameters We have: - Initial velocity (u) - Constant acceleration (a) - Time duration (t) ### Step 2: Use the formula for average velocity The average velocity (V_avg) of an object moving with constant acceleration can be calculated using the formula: \[ V_{avg} = \frac{V_f + V_i}{2} \] where \(V_f\) is the final velocity and \(V_i\) is the initial velocity. ### Step 3: Calculate the final velocity The final velocity (V_f) after time t can be calculated using the equation of motion: \[ V_f = u + at \] ### Step 4: Substitute the values into the average velocity formula Now, substitute \(V_f\) and \(V_i\) into the average velocity formula: \[ V_{avg} = \frac{(u + at) + u}{2} \] ### Step 5: Simplify the expression Combine the terms in the numerator: \[ V_{avg} = \frac{2u + at}{2} \] ### Step 6: Final expression for average velocity Thus, the average velocity of the particle in the first t seconds is: \[ V_{avg} = u + \frac{at}{2} \] ### Conclusion The average velocity of the particle moving in a straight line with constant acceleration a and initial velocity u in the first t seconds is: \[ V_{avg} = u + \frac{at}{2} \] ---

To find the average velocity of a particle moving in a straight line with constant acceleration, we can follow these steps: ### Step 1: Understand the parameters We have: - Initial velocity (u) - Constant acceleration (a) - Time duration (t) ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • KINEMATICS OF A PARTICLE

    VMC MODULES ENGLISH|Exercise JEE MAIN (archive)|19 Videos
  • KINEMATICS OF A PARTICLE

    VMC MODULES ENGLISH|Exercise JEE Advanced (archive)|14 Videos
  • KINEMATICS OF A PARTICLE

    VMC MODULES ENGLISH|Exercise LEVEL 1|75 Videos
  • JEE MAIN REVISON TEST-23

    VMC MODULES ENGLISH|Exercise PHYSICS (SECTION 2)|1 Videos
  • LAWS OF MOTION

    VMC MODULES ENGLISH|Exercise IMPECCABLE|53 Videos

Similar Questions

Explore conceptually related problems

If average velocity of particle moving on a straight line is zero in a time interval, then

Identify the correct graph represeriting the motion of a particle along a straight line With constant acceleration with zero initial velocity.

Statement-I : A particle moves in a straight line with constant acceleration. The average velocity of this particle cannot be zero in any time interval. Statement-II : For a particle moving in straight line with constant acceleration, the average velocity in a time interval is (u+v)/(2) , where u and v are initial and final velocity of the particle of the given time interval.

The velocity-time graph of a particle moving along a straight line is shown is . The rate of acceleration and deceleration is constant and it is equal to 5 m s^(-2) . If the a average velocity during the motion is 20 m s^(-1) , Then . The value of t is.

Assertion: When a particle moves with constant velocity its average velocity, its insttantaneous velocity and its speed are all equal in magnitude. Reason: If the average velocity of a particle moving on a straight line is zero in a time interval, then it is possible that the instantaneous velocity is never zero in the internal.

The velocity-time graph of a particle moving along a straight line is shown is Fig. The rate of acceleration and deceleration is constant and it is equal to 5 m s^(-2) . If the a average velocity during the motion is 20 m s^(-1) , Then . The maximum velocity of the particle is .

The velocity-time graph of a particle moving along a straight line is shown is Fig. The rate of acceleration and deceleration is constant and it is equal to 5 m s^(-2) . If the a average velocity during the motion is 20 m s^(-1) , Then . The maximum velocity of the particle is .

A particle moves in straight line. Acceleration of particle changes with velocity as showns in graph:

The velocity of a particle moving with constant acceleration at an instant t_(0) is 10m//s After 5 seconds of that instant the velocity of the particle is 20m/s. The velocity at 3 second before t_(0) is:-

A particle is moving along a straight line with constant acceleration. At the end of tenth second its velocity becomes 20 m//s and tenth second it travels a distance od 10 m . Then the acceleration of the particle will be.