A ball is dropped from a height. If it takes 0.200 s to cross thelast 6.00 m before hitting the ground, find the height from which it was dropped. `Take g=10 m/s^2`.

Explanation

It takes 0.2 s to reach from B to C.
Velocity at B can be calculated using
` 6=u (0.2) +(1)/(2) (10)(0.04) " "rArr " "u= 29m//s`
Distance between A & B can be calculated using ` (29)^(2) =0+2(10) S `
` S= ( (29)^(2))/( 20 ) =42m`
` (##VMC_PHY_XI_WOR_BOK_01_C02_E03_019_S01.png" width="80%">
Total height `= 42 +6=48m" "therefore " "x= 8 .`