The velocity-time graph of a particle moving along a straight line is shown in fig. The rate of acceleration and deceleration is constant and it is equal to `5 m s^(-2)`. If the average velocity during the motion is `20 m s^(-1)`, Then .
The distace travelled with uniform velcoty is .

Options

A. ` 5 s `
B. ` 10 s `
C. ` 20 s `
D. ` 5 sqrt 2 s`

Answer

A

Explanation

Average speed ` =20 ms^(-1) `
` (##VMC_PHY_XI_WOR_BOK_01_C02_E03_027_S01.png" width="80%">
` ("Total distance ")/( "Total time") =20 rArr ( "Area of graph")/( 20 + t) = 20 rArr (1)/(2) (20 +t+20 - t ) xx 5t = 20 (20 +t) rArr t5s `