The velocity-time graph of a particle moving along a straight line is shown is Fig. The rate of acceleration and deceleration is constant and it is equal to `5 m s^(-2)`. If the a average velocity during the motion is `20 m s^(-1)`, Then
.
The maximum velocity of the particle is .

Options

A. ` 20 ms^(-1) `
B. ` 25 ms^(-1)`
C. ` 30 ms^(-1)`
D. ` 40 ms^(-1) `

Answer

B

Explanation

Maximum velocity `= 5t = 5 xx 5 = 25 ms^(-1) `