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A particles starts sliding down a fricti...

A particles starts sliding down a frictionless inclined plane. If `S_n` is the distance travelled by it from time t= n-1 second to t = n second, the ratio `S_n//S_(n+1)` is

A

`(2n-1)/(2n+1)`

B

`(2n+1)/(2n)`

C

`(2n)/(2n+1)`

D

` (2n+1)/(2n-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
` S_n =(a)/(2) (2n-1) ,S_(n+1)=(a)/(2) (2n+1) " "rArr " "(S_n)/(S_(n+1) ) =(2n-1)/(2n+1) `
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