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Four persons K,L,M,N are initially at th...

Four persons K,L,M,N are initially at the four corners of a square of side d. Each person now moves with a uniform speed v in such a way that K always moves directly towards L, L directly towards M, M directly towards N, and N directly towards K. The four persons will meet at a time............. .

Text Solution

Verified by Experts

The correct Answer is:
D
` ((d)/(v)) ` By symmetry, we can say that all will meet at
the centre of square.
Component of velocity along KO (or LO etc) at any instant will be ` v cos 45^(@) or (v)/(sqrt2))`
Further distance KO ` =sqrt( 2) ((d)/(2)) =(d)/(sqrt(2)) " "therefore "Time "=(d//sqrt2)/(v//sqrt2)=(d)/(v) `
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