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A particle of mass `m` moving with a velocity `u` makes an elastic one-dimensional collision with a stationary particle of mass `m` establishing a contact with it for extermely small time. `T`. Their force of contact increases from zero to `F_0` linearly in time `T//4`, remains constant for a further time `T//2` and decreases linearly from `F_0` to zero in further time `T//4` as shown. The magnitude possessed by `F_0` is.
.

A

`(m u)/T`

B

`(2m u)/(T)`

C

`(4m u)/(3 T)`

D

`(3 m u)/(4T)`

Text Solution

Verified by Experts

The correct Answer is:
C

Impulse on particle m = Area under `F - t "curve" = (F_(0)(T + T/2))/(2) = m (0 - u)`
`:. F_(0) = (4 m u)/(3T)`.
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