A body of mass `m`, accelerates uniformly from rest to `V_(1)` in time `t_(1)`. The instantaneous power delivered to the body as a function of time `t` is.

Options

A. `(m v _(1) t^(2))/(t_(1))`
B. `(m v_(1)^(2) t)/(t_(1)^(2))`
C. `(m v _(1) t)/(t_(1))`
D. `(m v_(1)^(2) t)/(t_(1))`

Answer

B

Explanation

Here, applying`v = u + at`, we get , `v_1 = at_1 "ora" = (v_1)/(t_1)` ,Also `v = at = (v_1)/(t_1) xx t`
Power = `|vecF cdot vecv| = m av = m [(v_1)/(t_1)] [(v_1)/(t_1) xx t] = (m v_1^2 t)/(t_1^2).`