Three particles of masses `50 g, 100 g` and `150 g` are placed at the vertices of an equilateral triangle of side `1 m` (as shown in the figure). The (x,y) coordinates of the centre of mass will be :
.

Options

A. `(7/12 m, (sqrt3)/(4) m)`
B. `((sqrt3)/4 m, (5)/(12) m)`
C. `(7/12 m, (sqrt3)/(8) m)`
D. `((sqrt3)/8 m, (7)/(12) m)`

Answer

A

Explanation

Coordinates of the masses:
`m_1 : (0,0) " " m_2 : (1,0) " "m_3 = (10.5 , 0.5sqrt(3))/(50 + 100 + 150) = (sqrt3)/4 m`
Coordinates of CM : `(7/12, (sqrt3)/4)`.