A light inextensible string that gas over a smoth fixed polley as shown in the figure connect two blocks of mases it `0.36` kg and `0.72` kg Taking `g = 10 ms^(-2)` , find the work done by the string on the block of mass ` 0.36` kg doring the first second after the system is released from rest ,

Answer

8

Explanation

`2mg - T = 2ma`
`T - mg = ma`
`a = g/3`
`T = (4 mg)/(3)`
`W = T xx s = T xx 1/2 at^2 = 8J`.