A wooden block is floating in a liquid 50 % of its volume is inside the liquid when the vessel is stationary. Percentage of volume immersed when the vessel moves upwards with an acceleration `a = g//2` is

Options

A. ` 75 % `
B. `25% `
C. `50 % `
D. `33.33 % `

Answer

C

Explanation

When vessel is stationary: ` V rho _w g = V _i rho _L g rArr (V_i)/(V) = (rho _w)/(rho_L) `
When vessel moves upwards with acceleration ` (g)/(2) : B - mg = ma `
` rArr V_i rho _L (g + (g)/(2)) - Vrho _w g = ((V rho _w g )/(2)) rArr (V'_i)/(V) = (rho_w ) /(rho _L ) therefore (V'_i ) /(V) = (V_i ) /(V) ` Hence no charge