A cubical box of wine has a small spout located in one of the bottom corners. When the box is full and placed on a level surface, opening the spout results in a flow of wine with a speed of `v_(0)` When the box is half empty, someone lift it at `45^(@)` so that the spout is at the lowest point. When the spout is opened, the wine flow out with a speed of

Options

A. ` v_ 0 `
B. ` v _ 0//2 `
C. ` (v _ 0 ) /(sqrt2 ) `
D. ` (v_0)/(4sqrt2) `

Answer

D

Explanation

` v_ 0 = sqrt (2ga ) , v' = sqrt(2g (a)/(sqrt2)) = (v_0)/(4sqrt2 ) `