There are two identical small holes of area of cross section a on the opposite sides of a tank containing liquid of density `rho`. The differences in height between the holes is `h`. The tank is resting on a smooth horizontal surface. The horizontal force which will have to be applied on the tank to keep it in equilibrium is

Options

A. ` gh rho a `
B. ` (2 gh ) /( rho a ) `
C. ` 2 rho a g h `
D. ` (rho gh ) /(a ) `

Answer

C

Explanation

Force applied net ` = rho a v _ 1 ^ 2 - rho a v _ 1 ^ 2 = rho a (2 gh_1) - rho a (2 gh _ 2 ) = 2 rho a g (h_ 1 - h _ 2) = 2 rho a gh `