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A container (see figure) contains a liquid upto a height h. The density of the liquid is The gauge pressure at point P is ` (rho gh )/(x ) `. Find the value of ` x `

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The correct Answer is:
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Gauge pressure at the depth H is ` rho g H`. The depth of point P is ` (h)/(2) therefore P_("gauge") = rho g ((h)/(2))`
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