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There is a circular tube in a vertical p...

There is a circular tube in a vertical plane. Two liquids which do not mix and of densities `d_(1)` and `d_(2)` are filled in the tube. Each liquid subtends `90^(@)` angle at centre. Radius joining their interface makes an angle `alpha` with vertical . rartio `d_(1)//d_(2)` is

A

` ( 1 + tan alpha )/(1 - tan alpha ) `

B

` ( 1 + sin alpha ) /(1 - cos alpha ) `

C

` (1 + sin alpha )/(1 - sin alpha ) `

D

` (1 + cos alpha )/(1 - cos alpha ) `

Text Solution

Verified by Experts

The correct Answer is:
A

Equating pressure at A
`(Rcosalpha+Rsinalpha)d_(2)g=(Rcosalpha-Rsinalpha)d_(1)g`
`Rightarrow(d_1)/(d_2)=(cosalpha+sinalpha)/(cosalpha-sinalpha)=(1+tanalpha)/(1-tanalpha)`
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