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Six identical cunducting rods are joined...


Six identical cunducting rods are joined as shown in Fig. Points A and D are maintained at temperatures `200^@C` and `20^@C` respectively. The temperature of junction B will be

A

`120^(@)C`

B

`100^(@)C`

C

`140^(@)C`

D

`80^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
C
We have `H=(KADeltaT)/(l)or,DeltaT=H((l)/(KA))`
Take `(l)/(KA)` as thermal resistance

As `R_(AB)=R_(BC)=R_(CD)`
So, temperature drop through each resistor will be same `=(180)/(3)=60^(@)C`
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