A combination of capacitors given is charged by a cell of emf E as shown :
If it is given that `V_(ab)` i.e. potential difference between points a and b is 4V, then answer the given questions.
Potential difference between points d and a will be :

Options

A. 4 V
B. 12 V
C. 10 V
D. 8 V

Answer

C

Explanation

In given circuit, there are two portions marked I and II as shown.

Now, considering circuit as given in figure

Clearly I and II parts are in series, so charge on both portions must be same
As `V_(ac)=12V`
And `C_(eq)` of portion marked `I=10muF`
So charge on portion II=`120muC implies C_(ad)xx(V_(d)-V_(a))=120muC`
`implies 12xx(V_(d)-V_(a))=120" "{therefore C_(ad)=12muF} implies V_(d)-V_(a)=10V`.