In figure , the plates of a parallel plate capacitors have unequal charges. Its capacitance is C. P is a point outside the capacitor and close to the plate of charge -Q. The distance between the plates is d. Then

Options

A. A point charge at point ‘P’ will experience electric force due to capacitor
B. The potential difference between the plates will be `(3Q)/(2C)`
C. The energy stored in the electric field in the region between the plates is `(9Q^(2))/(8C)`
D. The force on one plate due to the other plate is `(Q^(2))/(8C)`

Answer

A, B, C

Explanation

Energy `=(1)/(2)epsi_(0)E^(2)Ad=(1)/(2)epsi_(0)((3Q)/(2Cd))^(2)Ad=(9)/(8)(Q^(2))/(C)`