Two capacitors of `2muF` and `3muF` are charged to `150 V` and `120 V`, respectively. The plates of capacitor are connected as shown in the figure. An uncharged capacitor of capacity `1.5muF` falls to the free end of the wire. Then

Options

A. Charge on the `1.5muF` capacitor will become `180muC`
B. Charge on the `2muF` capacitor will become `120muC`
C. +ve charge flows through A from left to right
D. +ve charge flows through A from right to left

Answer

A, B, C

Explanation

In the initial state, charge on each capacitor is shown in figure-1

let charge q flow anticlockwise in the circuit before it achieves steady state as shown in figure-2 Applying KVL in figure 2.
`(-360+q)/(3)+(q)/(1.5)-((300-q))/(2)=0 or q=180muC`
`therefore`Final charge on `1.5muF` capacitor is q=180`muC` and final charge on `2muF` capacitor is `300-q=120muC`.