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Consider a disconnected plate capacitor ...

Consider a disconnected plate capacitor of capacity `10 muF` with air filled in the gap between the plates. Now one-half of the space between the plates is filled with a dielectric of dielectric constant `4` as shown in .The capacity of the capacitor changes to
.

A

`25muF`

B

`20muF`

C

`40muF`

D

`5muF`

Text Solution

Verified by Experts

The correct Answer is:
A
Given `(epsi_(0)A)/(d)=10, C'=(epsi_(0)A//2)/(d)+(4epsi_(0)(A//2))/(d)=10[(1)/(2)+2]=25muF`.
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