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A parallel plate condenser with a dielec...

A parallel plate condenser with a dielectric constant K between the plates has a capacity C and is charged to a potential V volt. The dielectric slab is slowly removed from, between the plates and then reinserted. The work done by the system in this process is

A

`(1)/(2)(K_1)CV^(2)`

B

`CV^(2)(K-1)//K`

C

`(K-1)CV^(2)`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
D

On introduction and removal and again on introduction, the capacity and potential remain same. So, net work done by the system in this process `W=U_(f)-U_(i)=(1)/(2)CV^(2)-(1)/(2)CV^(2)=0`.
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