A parallel plate capacitor is made of two circular plates separated by a distance of 5 mm and with a dielectric of dielectric constant 2.2 between them. When the electric field in the dielectric is`3 xx 10^(4) V//m`, the charge density of the positive plate will be close to :

Options

A. `6xx10^(-7)C//m^(2)`
B. `3xx10^(-7)C//m^(2)`
C. `3xx10^(4)C//m^(2)`
D. `6xx10^(4)C//m^(2)`

Answer

A

Explanation

Electric field inside dielectric `E=(sigma)/(Kepsi_(0))=3xx10^(4)`
`implies sigma=2.2xx8.58xx3xx10^(4)xx10^(-12)=6.6xx8.85xx10^(-8)=5.841xx10^(-7)~~6xx10^(-7)c//m^(2)`.