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A parallel plate capicitaor with plates ...

A parallel plate capicitaor with plates of area `1m^2` each, are at a separation of `0.1`m. If the electric field between the plates is 100 `N//C`, the magnitude of charge on each plate is : (Take `epsilon=8.85xx10^-12(C^2)/(N-m^2)`)

A

`8.85xx10^(-10)C`

B

`9.85xx10^(-10)C`

C

`7.85xx10^(-10)C`

D

`6.85xx10^(-10)C`

Text Solution

Verified by Experts

The correct Answer is:
A

`d=0.1M" , "A=1M^(2)`
`E=(Q)/(Ain_(0))` , , `Q=Eaepsi_(0)=100xx1m^(2)xx8.85xx10^(-12)=8.85xx10^(-10)C`.
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