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A 4 muF capacitor and a resistance of 2....

A `4 muF` capacitor and a resistance of `2.5 M Omega` are series 12 V battery. Find the time after with the potential difference across the capacitor is 3 times the potential difference across the resistance [Given `ln(2) = 0.693`]

A

13.80s

B

6.93s

C

7s

D

14s

Text Solution

Verified by Experts

The correct Answer is:
A
Given `V_c=3V_R=3(V-V_c)` Here V is the applied potential
`therefore V_c=3/4V or V(1-e^(-t//tau_0))=3/4V therefore e^(-t//tau_0)=1/4`…….(i)
Here `tau_c=CR=10s`
Subsituting this value of `tau_c` in Eq(i) and solving for t, we get
`therefore t=13.86s therefore` Correct answer is (A)
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