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A parallel plate capacitor C with plates...

A parallel plate capacitor C with plates of unit area and separaion d is filled with a liquid of dielectric constant K = 2. The level of liquid is `d//3` initially. Suppose the liquid level decreases at a constant speed V. the time constant as a function of time t is

A

`(6epsilon_(0)R)/(5d+3vt)`

B

`((15d+9vt)epsilon_(0)R)/(2d^(2)-3dvt-9v^(2)t^(2))`

C

`(6epsilon_(0)R)/(5d-3vt)`

D

`((15d-9vt)epsilon_(0)R)/(2d^(2)+3dvt-9v^(2)t^(2))`

Text Solution

Verified by Experts

The correct Answer is:
A
After time ,t thickness of liquid eill remain `(d-/3-vt)`
Now time constant as function of time `tau_e=CR(epsilon_0(1)R)/((d-d/3+vt)+(d//3-vt)/(2))("applying " c=(epsilon_0A)/(d-t+t/K))=(6epsilon_0R)/(5d+3vt)`
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Knowledge Check

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