A part of a circuit in steady state along with the currents flowing in the branches,the values of resistances,etc, is shown in figure.Calculate the energy stored in the capacitor.

Answer

288

Explanation

Using Kirchhoff's first law at junction a and b, we have found the current in other wires of the circuit on which currents where not shown
Now,to calculate the energy stored in the capacitor we will have to first the potential difference `V_(ab)` across it.
`V_a-3xx5-3xx1+3xx2=V_b`
`therefore V_a-V_(b)=V_(ab)=12V`
`therefore U=1/2CV_(ab)^(2)=1/2(4xx10^(-6))(12^(2))J=0.288 mJ =288 muJ`