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A circular coil of wire consisting of 10...

A circular coil of wire consisting of 100 turns, each of radius 8.0 cm carries a current of 0.40 A. What is the magnitude of the magnetic field B at the centre of the coil?

Text Solution

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Number of turns on the circular coil, n = 100 , Radius of each turn, r = 8.0 cm = 0.08 cm
Current flowing in the coil, `I=0.4A`
Magnitude of the magnetic field at the centre of the coil is given by the relation,
`|B|=(mu_(0))/(4pi)(2pinI)/r` , `mu_(0)=` Permeability of free space , `=4pixx10^(-7)TmA^(-1)`
`|B|=(4pixx10^(-7))/(4pi)xx(2pixx100xx0.4)/0.08=3.14xx10^(-4)T`
Hence, the magnitude of the magnetic field is `3.14xx10^(-4)T`
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