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The bisector of the acute angle formed b...

The bisector of the acute angle formed between the lines 4x - 3y + 7 = 0 and 3x - 4y + 14 = 0 has the equation

A

`x+y-7=0`

B

`x-y+3=0`

C

`2x+y-11=0`

D

`x+2y-12=0`

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The correct Answer is:
To find the equation of the bisector of the acute angle formed between the lines \(4x - 3y + 7 = 0\) and \(3x - 4y + 14 = 0\), we can follow these steps: ### Step 1: Identify the coefficients The equations of the lines can be expressed in the standard form \(A_1x + B_1y + C_1 = 0\) and \(A_2x + B_2y + C_2 = 0\). For the first line \(4x - 3y + 7 = 0\): - \(A_1 = 4\) - \(B_1 = -3\) - \(C_1 = 7\) For the second line \(3x - 4y + 14 = 0\): - \(A_2 = 3\) - \(B_2 = -4\) - \(C_2 = 14\) ### Step 2: Use the angle bisector formula The formula for the angle bisector between two lines is given by: \[ \frac{A_1x + B_1y + C_1}{\sqrt{A_1^2 + B_1^2}} = \pm \frac{A_2x + B_2y + C_2}{\sqrt{A_2^2 + B_2^2}} \] ### Step 3: Calculate the square roots First, we calculate the denominators: \[ \sqrt{A_1^2 + B_1^2} = \sqrt{4^2 + (-3)^2} = \sqrt{16 + 9} = \sqrt{25} = 5 \] \[ \sqrt{A_2^2 + B_2^2} = \sqrt{3^2 + (-4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5 \] ### Step 4: Substitute into the formula Now substituting into the angle bisector formula: \[ \frac{4x - 3y + 7}{5} = \pm \frac{3x - 4y + 14}{5} \] ### Step 5: Simplify the equation Since both sides are divided by 5, we can multiply through by 5 to eliminate the denominator: \[ 4x - 3y + 7 = \pm (3x - 4y + 14) \] This gives us two cases to consider: **Case 1:** \[ 4x - 3y + 7 = 3x - 4y + 14 \] Rearranging gives: \[ 4x - 3x + 4y - 3y + 7 - 14 = 0 \] \[ x + y - 7 = 0 \quad \text{(1)} \] **Case 2:** \[ 4x - 3y + 7 = -(3x - 4y + 14) \] Rearranging gives: \[ 4x - 3y + 7 = -3x + 4y - 14 \] \[ 4x + 3x - 3y - 4y + 7 + 14 = 0 \] \[ 7x - 7y + 21 = 0 \] \[ x - y + 3 = 0 \quad \text{(2)} \] ### Step 6: Identify the acute angle bisector To determine which of these represents the acute angle bisector, we check the sign of \(A_1A_2 + B_1B_2\): \[ A_1A_2 + B_1B_2 = 4 \cdot 3 + (-3)(-4) = 12 + 12 = 24 > 0 \] Since this is positive, we use the negative sign in the angle bisector formula, which corresponds to equation (2): \[ x - y + 3 = 0 \] ### Final Answer The equation of the bisector of the acute angle formed between the lines is: \[ x - y + 3 = 0 \]
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