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For the hyperbola `(x^(2))/(a^(2))+(y^(2))/(b^(2))=1`, the normal at point P meets the transverse axis AA' in G and the connjugate axis BB' in g and CF be perpendicular to the normal from the centre. Q. The value `PE*Pg` is equal to

A

`b^2`

B

`a^2`

C

`ab`

D

`a^2b^2`

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The correct Answer is:
A
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