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If theta is eliminated from the equation...

If `theta` is eliminated from the equations `a sec theta-x tan theta=y" and "b sec theta+y tan theta=x` (a and b are constants), then :

A

the director circle of the hyperbola `(x^2)/(a^2)-(y^2)/(b^2)=1`

B

auxiliary circle of the ellipse `(x^2)/(a^2)+(y^2)/(b^2)=1`

C

director circle of the ellipse `(x^2)/(a^2)+(y^2)/(b^2)=1`

D

director circle of the circle `x^2+y^2=(a^2+b^2)/(2)`

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The correct Answer is:
To eliminate \( \theta \) from the given equations \( a \sec \theta - x \tan \theta = y \) and \( b \sec \theta + y \tan \theta = x \), we will follow these steps: ### Step 1: Rewrite the equations using trigonometric identities The first equation is: \[ a \sec \theta - x \tan \theta = y \] Using the identities \( \sec \theta = \frac{1}{\cos \theta} \) and \( \tan \theta = \frac{\sin \theta}{\cos \theta} \), we can rewrite this as: \[ \frac{a}{\cos \theta} - x \frac{\sin \theta}{\cos \theta} = y \] Multiplying through by \( \cos \theta \): \[ a - x \sin \theta = y \cos \theta \] Rearranging gives: \[ x \sin \theta + y \cos \theta = a \tag{1} \] ### Step 2: Rewrite the second equation The second equation is: \[ b \sec \theta + y \tan \theta = x \] Again using the identities: \[ \frac{b}{\cos \theta} + y \frac{\sin \theta}{\cos \theta} = x \] Multiplying through by \( \cos \theta \): \[ b + y \sin \theta = x \cos \theta \] Rearranging gives: \[ x \cos \theta - y \sin \theta = b \tag{2} \] ### Step 3: Square and add the two equations Now we will square both equations and add them: \[ (x \sin \theta + y \cos \theta)^2 + (x \cos \theta - y \sin \theta)^2 = a^2 + b^2 \] Expanding both sides: \[ (x^2 \sin^2 \theta + 2xy \sin \theta \cos \theta + y^2 \cos^2 \theta) + (x^2 \cos^2 \theta - 2xy \sin \theta \cos \theta + y^2 \sin^2 \theta) = a^2 + b^2 \] Combining like terms: \[ x^2 (\sin^2 \theta + \cos^2 \theta) + y^2 (\sin^2 \theta + \cos^2 \theta) = a^2 + b^2 \] Using the identity \( \sin^2 \theta + \cos^2 \theta = 1 \): \[ x^2 + y^2 = a^2 + b^2 \] ### Step 4: Conclusion The final equation \( x^2 + y^2 = a^2 + b^2 \) represents the equation of the director circle of an ellipse.
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