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The focal chord to y^2=16 x is tangent t...

The focal chord to `y^2=16 x` is tangent to `(x-6)^2+y^2=2.` Then the possible value of the slope of this chord is `{-1,1}` (b) `{-2,2}` `{-2,1/2}` (d) `{2,-1/2}`

A

`{-1,1}`

B

`{-2,2}`

C

`{-2,(1)/(2)}`

D

`{2,-(1)/(2)}`

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The correct Answer is:
A
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