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If tangents are drawn to the ellipse `x^2+2y^2=2,` then the locus of the midpoint of the intercept made by the tangents between the coordinate axes is (a) `1/(2x^2)+1/(4y^2)=1` (b) `1/(4x^2)+1/(2y^2)=1` (c) `(x^2)/2+y^2=1` (d) `(x^2)/4+(y^2)/2=1`

A

`(1)/(2x^2)+(1)/(4y^2)=1`

B

`(1)/(4x^2)+(1)/(2y^2)=1`

C

`(x^2)/(2)+(y^2)/(4)=1`

D

`(x^2)/(4)+(y^2)/(2)=1`

Text Solution

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The correct Answer is:
A
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