Home
Class 12
CHEMISTRY
The benzene molecule is :...

The benzene molecule is :

A

`6sigma` bonds and `3pi` bonds

B

`12sigma` bonds and `3pi` bonds

C

`6sigma` bonds and `6pi` bonds

D

`9sigma` bonds and `3pi` bonds

Text Solution

AI Generated Solution

The correct Answer is:
To determine the characteristics of the benzene molecule, we can follow these steps: ### Step 1: Identify the Molecular Formula The first step is to recognize that the molecular formula of benzene is C₆H₆. This indicates that there are six carbon atoms and six hydrogen atoms in the molecule. **Hint:** Remember that the molecular formula gives you the number of each type of atom in the molecule. ### Step 2: Understand the Structure of Benzene Benzene has a cyclic structure, meaning the carbon atoms are arranged in a ring. Each carbon atom is bonded to two other carbon atoms and one hydrogen atom. **Hint:** Visualize the benzene ring as a hexagon where each vertex represents a carbon atom. ### Step 3: Identify the Types of Bonds In benzene, there are alternating single and double bonds between the carbon atoms. However, due to resonance, benzene is often represented as having equal bond lengths, indicating that it has delocalized electrons. **Hint:** Recall that resonance structures can help explain the stability of benzene. ### Step 4: Count the Sigma and Pi Bonds - **Sigma Bonds:** Each carbon-carbon bond and carbon-hydrogen bond is a sigma bond. In benzene, there are 6 carbon-hydrogen bonds and 6 carbon-carbon bonds, resulting in a total of 12 sigma bonds. - **Pi Bonds:** The alternating double bonds contribute to pi bonds. In benzene, there are 3 double bonds, which means there are 3 pi bonds. **Hint:** Remember that a single bond consists of one sigma bond, a double bond consists of one sigma and one pi bond, and a triple bond consists of one sigma and two pi bonds. ### Step 5: Conclusion From the above analysis, we conclude that the benzene molecule contains 12 sigma bonds and 3 pi bonds. **Final Answer:** The benzene molecule is characterized by having 12 sigma bonds and 3 pi bonds. ---

To determine the characteristics of the benzene molecule, we can follow these steps: ### Step 1: Identify the Molecular Formula The first step is to recognize that the molecular formula of benzene is C₆H₆. This indicates that there are six carbon atoms and six hydrogen atoms in the molecule. **Hint:** Remember that the molecular formula gives you the number of each type of atom in the molecule. ### Step 2: Understand the Structure of Benzene ...
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL BONDING-I & II

    VMC MODULES ENGLISH|Exercise Level - 2 (JEE Advanced)|50 Videos
  • CHEMICAL BONDING-I & II

    VMC MODULES ENGLISH|Exercise JEE Main (Numerical Value Questions)|15 Videos
  • CHEMICAL BONDING-I & II

    VMC MODULES ENGLISH|Exercise Level - 0 (Long Answer Type)|4 Videos
  • CHEMICAL BONDING & MOLECULAR STRUCTURE

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE-L|9 Videos
  • CHEMICAL EQUILIBRIUM

    VMC MODULES ENGLISH|Exercise IN-CHAPTER EXERCISE - G|10 Videos

Similar Questions

Explore conceptually related problems

The carbon-carbon bond length in benzene molecule is:

How many sigma and pi bonds are present in a benzene molecule ? .

How many sigma bonds and pi bonds are present in a benzene molecules ? .

How many sigma bonds and pi bonds are present in a benzene molecules ? .

Intermolecular forces between two benzene molecules are nearly of same strength as those between two toluene molecules. For a mixture of benzene and toluene, which of the following are not true?

How many sigma and pi bonds are present in a benzene molecule?

On adding 1g arsenic to 80 g benzene, the freezing point of benzene is lowered by 0.213^(@)C . The formula of arsenic molecule is : (Atomic mass of arsenic = 75) ( K_(f) = 5.12 K kg/mol)

Which of the following molecules is most suitable to disperse benzene in water?

1 g of arsenic dissolved in 86 g of benzene brings down the freezing point to 5.31^@C from 5.50^@C .If K_f of benzene is 4.9 (.^(@)C)/m , the atomicity of the molecule is : (As =75 or As GAM 75)