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Which of the following ions has an (18 +...

Which of the following ions has an (18 + 2) electronic configuration ?

A

`Cu^(+)`

B

`Fe^(3+)`

C

`Pb^(2+)`

D

`Xe^(2+)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the following ions has an (18 + 2) electronic configuration, we need to analyze the electronic configurations of the given ions and see which one has 18 electrons in the inner shell and 2 electrons in the outermost shell (valence shell). ### Step-by-Step Solution: 1. **Understanding (18 + 2) Configuration**: - The notation (18 + 2) means that there are 18 electrons in the inner shells and 2 electrons in the outermost shell (valence shell). 2. **Analyzing Each Ion**: - We will go through each option one by one to find the correct electronic configuration. 3. **Option 1: Copper Ion (Cu⁺)**: - The electronic configuration of neutral copper (Cu) is: \[ \text{Cu: } [\text{Ar}] 3d^{10} 4s^1 \] - For Cu⁺, we remove one electron from the 4s orbital: \[ \text{Cu}^+: [\text{Ar}] 3d^{10} \] - Here, there are no electrons in the valence shell (4s), so this option is incorrect. 4. **Option 2: Iron Ion (Fe³⁺)**: - The electronic configuration of neutral iron (Fe) is: \[ \text{Fe: } [\text{Ar}] 3d^6 4s^2 \] - For Fe³⁺, we remove two electrons (first from 4s, then from 3d): \[ \text{Fe}^{3+}: [\text{Ar}] 3d^5 \] - Again, there are no electrons in the valence shell, so this option is also incorrect. 5. **Option 3: Lead Ion (Pb²⁺)**: - The electronic configuration of neutral lead (Pb) is: \[ \text{Pb: } [\text{Xe}] 4f^{14} 5d^{10} 6s^2 6p^2 \] - For Pb²⁺, we remove two electrons from the 6p orbital: \[ \text{Pb}^{2+}: [\text{Xe}] 4f^{14} 5d^{10} 6s^2 \] - Here, there are 2 electrons in the valence shell (6s), which matches our requirement of (18 + 2). Thus, this option is correct. 6. **Option 4: Xenon Ion (Xe²⁺)**: - The electronic configuration of neutral xenon (Xe) is: \[ \text{Xe: } [\text{Kr}] 4d^{10} 5s^2 5p^6 \] - For Xe²⁺, we remove two electrons from the 5p orbital: \[ \text{Xe}^{2+}: [\text{Kr}] 4d^{10} 5s^2 5p^4 \] - In this case, there are 4 electrons in the valence shell (5s and 5p), so this option is incorrect. ### Conclusion: The ion that has an (18 + 2) electronic configuration is **Lead Ion (Pb²⁺)**.

To determine which of the following ions has an (18 + 2) electronic configuration, we need to analyze the electronic configurations of the given ions and see which one has 18 electrons in the inner shell and 2 electrons in the outermost shell (valence shell). ### Step-by-Step Solution: 1. **Understanding (18 + 2) Configuration**: - The notation (18 + 2) means that there are 18 electrons in the inner shells and 2 electrons in the outermost shell (valence shell). 2. **Analyzing Each Ion**: ...
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